fetching data from json using php?

Question

I have a Json data retrieved from facebook using graph api, now i am going to parse that data, i decoded that json

$decodedjson= json_decode($jsondata);

after that i got data in following format. Image for Json data

i write

$id= $decodedjson->message_id;

to get the id, the attachment is an other object, please tell me how can i access the attachment, media, href, alt and the video , display_url and so on, name etc

Thanks

If you have difficulty traveresing objects, have you considered using arrays instead? If you provide true for the second variable in json_decode($jsondata,true);, it returns an assoc array instead. — Niklas
– Niklas, Commented Jun 22, 2011 at 8:18

tobyodavies · Accepted Answer · 2011-06-24 03:32:42Z

2

Just like any object -

$vid=($decodedjson[2])->attachment->media[0];
$alt=$vid->alt;

Edit: Noticed the [2]=>... at the top of your var_dump

edited Jun 24, 2011 at 3:32

answered Jun 22, 2011 at 8:22

tobyodavies

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2 Comments

Asghar Over a year ago

when i used it says Notice: Trying to get property of non-object in C:\wamp\www\display\index.php

tobyodavies Over a year ago

I've just noticed that this is a partial var_dump by the looks of it. If you're going to post a var dump, post the dump of the whole object - it looks like $decodedjson is in fact an array of objects based on the [2] =>... at the top...

Oyeme · Accepted Answer · 2011-06-22 08:18:23Z

0

json_decode - convert json format to php array You should access it as array

$id= $decodedjson[0]['message_id'];

 $attachment= $decodedjson[0]['attachment']['media'];//an array

$video= $decodedjson[0]['media'][0]['video']['owner'];

answered Jun 22, 2011 at 8:18

Oyeme

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2 Comments

tobyodavies Over a year ago

he's var_dumped it, it's clearly a stdClass, this answer doesn't add anything...

Asghar Over a year ago

$id= $decodedjson[0]['message_id']; is not correct because message_id is object and it will be accessed using $decodedjson[0]->message_id;

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