Replace string within all occurrences of a string character javascript

Question

I want to find exact occurrences of all \n and : and replace the string in between with a specific string.

For example, given this input:

 Testing \n string of character \n June,23 2020: the task was completed. \n April,4 2020: All looks \n good

The expected result is this:

 Testing \n string of character <br><b> June,23 2020</b><br> the task was completed. <br><b> April,4 2020</b></br> All looks \n good

const text=`Testing \n string of character \n June,23 2020: the task was completed. \n April,4 2020: All looks \n good`;
const newlineColonRegex = /(\n|:)/g

const replaceWith = '<br><b>'
const newString = text.replace(newlineColonRegex, replaceWith)
console.log(newString)

I edited your question to use code blocks instead of block quotes. In the process I also removed extra spaces in the <b> and <br> tags that I believe (based on your code snippet) were accidentally inserted by SO's blockquote code, but wanted to note it here in case those were intentional. — Daniel Beck
– Daniel Beck, Commented Jun 2, 2021 at 15:56

The fourth bird · Accepted Answer · 2021-06-02 16:11:23Z

1

You can exclude matching both using an negated character class.

\n([^\n:]+):

Replace with

<br><br>$1<br><br>

Regex demo

const regex = /\n([^\n:]+:)/g;
const text = `Testing \n string of character \n June,23 2020: the task was completed. \n April,4 2020: All looks \n good`;
const newlineColonRegex = /\n([^\n:]+):/g;

const replaceWith = '<br><br>$1<br><br>'
const newString = text.replace(newlineColonRegex, replaceWith)
console.log(newString)

If you also want to match it from the start of the string, you could use an anchor instead of a newline ^([^\n:]+:) and use the /gm flags

edited Jun 2, 2021 at 16:11

answered Jun 2, 2021 at 16:06

The fourth bird

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