URL loop in python

Question

I have been working with two APIs to fetch data from amazon.com. Using first API I am getting a series of ASINs (string) and now need to pass first 10 ASINs to second API URL to fetch "Product Description".

I am getting ASINs from first API in below format. All strings

B07BJL8CL2
B00CA6X50Y
B01LI4IDQO
B000HTENO8
B00XKXNGT6

Second API URL querystring_lookupProduct = {"url":"https://www.amazon.com/dp/B09BVQPNWZ"}

I have to dynamically replace the end part B09BVQPNWZ with ASINs I am getting from first API. Would really appreciate your help.

One is to convert ASIN in list but as I try to do this I get the response like this

['B', '0', '7', 'B', 'J', 'L', '8', 'C', 'L', '2']
['B', '0', '0', 'C', 'A', '6', 'X', '5', '0', 'Y']
['B', '0', '0', 'X', 'K', 'X', 'N', 'G', 'T', '6']
['B', '0', '1', 'L', 'I', '4', 'I', 'D', 'Q', 'O']

1) create a list of strings with ASIN (asin_to_fetch), then 2) iterate over this list: for asin in asin_to_fetch: ... and 3) use string formatting to build the desired URL: url="https://www.amazon.com/dp/{}".format(asin) — 0x6d64
– 0x6d64, Commented Jan 6, 2022 at 6:24

Ice · Accepted Answer · 2022-01-06 06:22:57Z

1

URL_TEMP = "https://www.amazon.com/dp/{}"

asins = ['B07BJL8CL2', 'B00CA6X50Y', 'B01LI4IDQO', 'B000HTENO8', 'B00XKXNGT6']

for asin in asins:
    url = URL_TEMP.format(asin)
    print(url)

answered Jan 6, 2022 at 6:22

Ice

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2 Comments

CodePak Over a year ago

Thanks for the reply however when I try to convert the asins in list using asin=list(asin) I am getting it in this format ['B', '0', '7', 'B', 'J', 'L', '8', 'C', 'L', '2'], ['B', '0', '7', 'B', 'J', 'L', '8', 'C', 'L', '2'] ['B', '0', '0', 'C', 'A', '6', 'X', '5', '0', 'Y'] ['B', '0', '0', 'X', 'K', 'X', 'N', 'G', 'T', '6'] ['B', '0', '1', 'L', 'I', '4', 'I', 'D', 'Q', 'O']

Ice Over a year ago

asin is not a string?

Abdusalam mohamed · Accepted Answer · 2022-01-06 07:31:01Z

0

url = 'https://www.amazon.com/dp/'
Dict = []// create a list to hold the urls


asins = ['B07BJL8CL2', 'B00CA6X50Y', 'B01LI4IDQO', 'B000HTENO8', 'B00XKXNGT6']

// iterate over the asins and populate your list with the values

For asin in asins:
   Dict.append(url + '/' + asin)

edited Jan 6, 2022 at 7:31

answered Jan 6, 2022 at 6:43

Abdusalam mohamed

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2 Comments

CodePak Over a year ago

Thanks for the reply however when I try to convert the asins in list using asin=list(asin) I am getting it in this format ['B', '0', '7', 'B', 'J', 'L', '8', 'C', 'L', '2']

Abdusalam mohamed Over a year ago

When asin is a string using the list func will break it down to characters, try changing the " for asin in asins " to " for i < count(asins) " and then using asin[i] as an index

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