Convert String to int[] array

Java 8 one liner would be:

int[] integers = Stream.of( numbers.split("") )
  .mapToInt(Integer::valueOf)
  .toArray();

If the above question is for Java.

 String numbers = "123456";
    int[] array = new int[numbers.length()];

        for (int i = 0; i < numbers.length(); i++) {
            array[i] = Character.getNumericValue(numbers.charAt(i));
            System.out.println("\n"+array[i]);
        }

The most straightforward way is to create an array variable and loop through the string characters and push them into the array.

var str = "123456";
var arr = [];

for (let n of str) {
  arr.push(parseInt(n))
}

console.log(arr);

The above answers are more straightforward ways to do achieve this; however, you can also take the substring of the array between a value of i and i+1, parse that string as an integer, and then assign the array at index i to the value of the integer to achieve the same goal. Here is the code below:

    public class StringtoIntArray {
        public static void main(String[] args) throws Exception 
        {
            String numbers = "123456";
            int[] array = new int[numbers.length()];

            String temp; 
            int holder;

            for(int i=0;i<numbers.length();i++)
            {
                temp=numbers.substring(i,i+1);
                holder = Integer.parseInt(temp);
                array[i]=holder;
                System.out.println(array[i]);
            }
        }
    }

I don't know what language you are working with. But I can tell you in c++.

character codes of digits start from 48(dec). You can add and remove this value for each element.

The code could roughly look like this.

int * _numbers=new int[numbers.size()];
for(int i=0;i<numbers.size();i++)
    _numbers[i]=numbers[i]-48;