Android: way to check if a string contains any values from array?

Question

I've tried searching for "Java check if string contains values from array", and other variations on that, but have not come up with anything so hoping someone can help me. I've got the following code that I would like to clean up:

if (dateint.contains("th")){
        dateint=dateint.substring(0, dateint.length()-2);
    } else if (dateint.contains("st")){
        dateint=dateint.substring(0, dateint.length()-2);
    } else if (dateint.contains("nd")){
        dateint=dateint.substring(0, dateint.length()-2);
    } else if (dateint.contains("rd")){
        dateint=dateint.substring(0, dateint.length()-2);
    }

I'm wondering if I can do something like the following (not true code, but thinking in code):

String[] ordinals = {"th", "st", "nd", "rd"};
if dateint.contains(ordinals) {
dateint=dateint.substring(0, dateint.length()-2);
}

basically checking if any of the values in the array are in my string. I'm trying to use the least amount of code reuqired so that it looks cleaner than that ugly if/else block, and without using a for/next loop..which may be my only option.

Knickedi · Accepted Answer · 2011-09-29 16:45:40Z

6

Try this:

for (String ord : ordinals) {
    if (dateint.contains(ord)) {
        dateint = dateint.substring(0, dateint.length() - 2);
        break;
    }
}

answered Sep 29, 2011 at 16:45

Knickedi

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1 Comment

Evan R. Over a year ago

Thanks this worked perfectly! thanks to everyone else who replied as well, was hoping for a 1/2 line solution using built in code but this will do.

Pang · Accepted Answer · 2015-01-05 07:10:13Z

3

If you are up to using other libraries, the Apache StringUtils can help you.

StringUtils.indexOfAny(String, String[])

if(StringUtils.indexOfAny(dateint, ordinals) >= 0)
    dateint=dateint.substring(0, dateint.length()-2);

edited Jan 5, 2015 at 7:10

Pang

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answered Sep 29, 2011 at 16:51

Danny

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Comments

anujprashar · Accepted Answer · 2011-09-29 16:48:50Z

1

you can use for loop for that

    for(int i = 0;i < ordinals.length;i++){
      if dateint.contains(ordinals[i]) {
        dateint=dateint.substring(0, dateint.length()-2);
        break;
       }

    }

answered Sep 29, 2011 at 16:48

anujprashar

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Comments

Avi · Accepted Answer · 2011-12-31 18:01:34Z

1

Use an extended for loop :

String[] ordinals = {"th", "st", "nd", "rd"};

for (String ordinal: ordinals) {
    if dateint.contains(ordinal) {
        dateint=dateint.substring(0, dateint.length()-2);
    }
}

edited Dec 31, 2011 at 18:01

Avi

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answered Sep 29, 2011 at 16:47

Gabriel Negut

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1 Comment

Noman Over a year ago

It saved me I used this logic to build my own...an it works :)

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