JavaScript - assignment - array of arrays

Question

var a = new Array();
var b = new Array();
var c = [a,b];

var str = 'hello,world,nice,day';
for(var i = 0; i < c.length; i++){
  c[i] = str.split(',');
}

After execution i'd like to have:

c = [a, b];
a = ['hello', 'world', 'nice', 'day'];
b = ['hello', 'world', 'nice', 'day'];

but really i have:

c = [['hello', 'world', 'nice', 'day'], ['hello', 'world', 'nice', 'day']];
a = [];
b = [];

could i fix it?

upd: Decision by Raynos is really nice. Thx.

I'm surprised you get a=null,b=null, shouldn't a and b be empty arrays? — themel
– themel, Commented Nov 4, 2011 at 19:21
When i wrote a=null, b=null it's mean they are empty arrays. Sorry for my mistake. — FSou1
– FSou1, Commented Nov 4, 2011 at 19:22

Raynos · Accepted Answer · 2011-11-04 19:21:04Z

5

for(var i = 0; i < c.length; i++){
  c[i].push.apply(c[i], str.split(','));
}

answered Nov 4, 2011 at 19:21

Raynos

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Comments

Some programmer dude · Accepted Answer · 2011-11-04 19:18:30Z

1

The split function creates a new array, that is stored in c. You have to loop through the array returned by split and do c[i].push() on that value.

Or just set a and b directly to the result of split.

answered Nov 4, 2011 at 19:18

Some programmer dude

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Comments

Itay P. · Accepted Answer · 2011-11-04 19:17:14Z

0

Because you wrote c[i] = str.split(','); - you should write c[i] = str.split(',')[i];
And actually - why go over it with for?

Edit - Sorry, thought the assignment was to c[0], c[1]....

answered Nov 4, 2011 at 19:17

Itay P.

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3 Comments

FSou1 Over a year ago

str.split(',')[i]. Are u sure about answer?

Raynos Over a year ago

that doesn't do what he wants at all

Itay P. Over a year ago

I'm sure about the syntax - but I've edited my answer, didn't noticed the first part of c = [a,b]

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