HTTP basic authentication, using python

Question

I want my users to go to a protected directory on my domain. Both .htaccess and .htpasswd are created and reside in the protected library.

The html that asks for a username/password combination is:

<form method="post" enctype="multipart/form-data" action="bin/logintest.cgi">
Username: <input type="text" name="username" size="20" value="please enter.."><br>
Password: <input type="password" name="password" size="20"><BR>
<input name="submit" type="submit" value="login">

The python cgi script is:

#!/usr/bin/python

import urllib2
import base64
import cgi

form = cgi.FieldStorage()
username = form.getfirst("username")
password = form.getfirst("password")

request = urllib2.Request("http://www.mydomain.com/protecteddir/index.html")
base64string = base64.encodestring('%s:%s' % (username, password)).replace('\n', '')
request.add_header("Authorization", "Basic %s" % base64string)
result = urllib2.urlopen(request)

print "Content-type: text/html\n\n"
print result

When I enter a correct username/password combination, the resulting 'webpage' is:

I suspect that my python code "print result" is not correct. How can I fix this?

chown · Accepted Answer · 2011-11-30 17:26:18Z

1

The returned object from a urlopen call is much like an open file stream, you need to read it to get the output.

Change print result to print result.read():

result = urllib2.urlopen(request)

print "Content-type: text/html\n\n"
print result.read()

Or, change result = urllib2.urlopen(request) to result = urllib2.urlopen(request).read():

result = urllib2.urlopen(request).read()

print "Content-type: text/html\n\n"
print result

Check out these examples: http://docs.python.org/library/urllib2.html#examples

_{_lunchbox}

edited Nov 30, 2011 at 17:26

answered Nov 30, 2011 at 17:07

chown

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Comments

Yugal Jindle · Accepted Answer · 2011-11-30 17:25:27Z

1

When you write :

resource = urllib2.urlopen(url)
# Here resource is your handle to the url
# resource provides a read function that mimics file read.

So, resource.read() # Reads the url like a file.

print resource # prints the repr for the resource object and not the actual content.

answered Nov 30, 2011 at 17:25

Yugal Jindle

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2 Comments

chown Over a year ago

Good addition about how it prints the repr of the object.

Paul van Toesmeer Over a year ago

Thank you, your suggestion is the same as @chown 's suggestion.

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