1 
set commands {
   "show phone xxx 11"
   "show phone yyy 22"
   "show phone zzz 33"
}

spawn ssh -o StrictHostKeyChecking=no $UserId@$host
sleep 15
#wait for password prompt
expect "*assword:"
#send password 
send -- "$Passwd\r"
sleep 5
foreach cmd $commands {
    set logfile [join [lrange [split $cmd] 2 end] _]
    log_file -a $logfile
    send -- "$cmd\r"
    expect -re "admin:"
    exp_sleep 8
    log_file
}

was not able redirect command's output to respective log file.

xxx_11 log file contains 'spawn ssh -o StrictHostKeyChecking=no $UserId@$host' output.
yyy_22 log file contains 'show phone xxx 11' command output.
zzz_33 log file contains 'show phone yyy 22' command output.

How to write log files in the following way:

XXX_11 log file contains 'show phone xxx 11' command output
yyy_22 log file contains 'show phone yyy 22' command output
zzz_33 log file contains 'show phone zzz 33' command output

Thanks in adavnce for help.

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  • 1
    You have used both the bash and zsh tags. What are the relevance of these tags to your question? Commented Nov 3, 2020 at 10:32
  • 1
    If you have your patterns correct, you don't need sleep. If you find you need to sleep, your patterns are wrong, and you should use expect -d script to debug the patterns. Commented Nov 3, 2020 at 18:54

1 Answer 1

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The first expect -re "admin:" will read the output of ssh up to the first admin: prompt. Presumably such a prompt is issued before you start sending commands.

You're missing an expect call before your loop to consume all the output sent so far before you send your commands. If you don't know what output to expect, you could replace your sleep 5 with an expect anything with timeout.

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  • Thanks stephane, by adding expect call before loop solved my issue. Commented Nov 8, 2020 at 18:29

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