How can I get the position of an argument by using its value?
For example:
myScript.sh hello world
echo "$1"
hello
How can I get the position of 'hello', which is 1 in this case?
2
1 Answer
While it wouldn't surprise me if there were quicker, easier ways, something like this should work:
#!/bin/bash
pos=0
found=no
for arg ; do
let pos++
if [[ "$arg" == "hello" ]] ; then
found=yes
break
fi
done
if [[ "$found" == "yes" ]] ; then
echo "Found hello at position $pos"
else
echo "hello not found"
fi
-
Thanks, I think this can work for now, but I hope there is a quicker way as you said.Lite Riyusaki– Lite Riyusaki2022-04-30 01:27:22 +00:00Commented Apr 30, 2022 at 1:27
printf '%s\0' "$@" | awk -vRS='\0' -vfind=hello '$0==find{print NR;exit}'(all POSIX). Omit exit if there may be multiple matches and you want all of them. You can also find the argument(s) containing a string withindex($0,find)or matching it as a regular expression with$0~find.