compare string with array values

Question

ArrayList<String> stylistidArr = new ArrayList<>();
ArrayList<String> durationArr = new ArrayList<>();
Integer duration = null;
stylistIDArray = differentGenderServicesAdapter.getSelectedStylistIdArray();
durationArray = differentGenderServicesAdapter.getSelectedDurArray();
for (int i = 0; i < stylistIDArray.size(); i++) {
    stylistidArr = stylistIDArray.get(i);
    durationArr = durationArray.get(i);
    if (stylistidArr.contains(stylistid)) {
        duration = Integer.parseInt(durationArr.get(i));
        Log.d("duration", String.valueOf(duration));
    }
}

I am having two arrays one is integer array and another one is string array also i am having one string i want to compare the string with all strings in an array if any of the array values matches with string i want to get integer value from integer array in that position. EX ArrayList<string> strvalue =(a,b,c,d,e),ArrayList<Integer>intValues=(1,2,3,4.5) and String str=c; .i want to get integer value 3.

The Impaler · Accepted Answer · 2018-06-11 17:38:32Z

2

A simple 'for' will do:

public Integer find(String searchedKey, List<String> keys, List<Integer> values) {
  for (int i = 0; i < keys.size() && i < values.size(); i++) {
    if (searchedKey.equals(keys.get(i))) {
      return values.get(i);
    }
  }
  return null;
}

And you can use it like this:

List<String> keys = new ArrayList<String>();
keys.add("a");
keys.add("b");
keys.add("c");
keys.add("d");
keys.add("e");

List<Integer> values = new ArrayList<Integer>();
values.add(1);
values.add(2);
values.add(3);
values.add(4);
values.add(5);

Integer value = find("c", keys, values);

answered Jun 11, 2018 at 17:38

The Impaler

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3 Comments

Deepa Over a year ago

for(int i=0;i<stylistIDArray.size() && i< durationArray.size();i++){ if(stylistid.equals(stylistIDArray.get(i))){ durArr=(durationArray.get(i)); } }

The Impaler Over a year ago

Ah... you are NOT using it as a function. You'll need to use break when you find it. Otherwise it always end up being null. Alternatively, I would recommend placing this logic into a function (as my example) since it's easier to read and to debug.

Deepa Over a year ago

thank you its working now instead of using array i used arrayoFarraylist that's why i got null.

Shivank Gupta · Accepted Answer · 2018-06-11 18:40:57Z

0

Try

for (int i = 0; i < stylistIDArray.size(); i++) {
stylistidArr = stylistIDArray.get(i);
durationArr = durationArray.get(i);
if(stylistidArr.equals(str){
// compares the ith element with "c"
k=values.get(i);
break;}
}

Use the value of k as needed.

answered Jun 11, 2018 at 18:40

Shivank Gupta

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2 Comments

Deepa Over a year ago

for (int i = 0; i < stylistIDArray.size(); i++) { stylistidArr = stylistIDArray.get(i); durationArr = durationArray.get(i); if(stylistidArr.equals(stylistid)){ strDuration=durationArr.get(i); // compares the ith element with "c" break; } }

Deepa Over a year ago

Its giving null

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